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3x^2+7x+4=14-2x
We move all terms to the left:
3x^2+7x+4-(14-2x)=0
We add all the numbers together, and all the variables
3x^2+7x-(-2x+14)+4=0
We get rid of parentheses
3x^2+7x+2x-14+4=0
We add all the numbers together, and all the variables
3x^2+9x-10=0
a = 3; b = 9; c = -10;
Δ = b2-4ac
Δ = 92-4·3·(-10)
Δ = 201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{201}}{2*3}=\frac{-9-\sqrt{201}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{201}}{2*3}=\frac{-9+\sqrt{201}}{6} $
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